JD1912 Relay Wiring Diagram Explained: Everything You Need to Know

If you’re an electrician or an automotive technician, chances are you’ve come across the JD1912 relay. This type of relay is commonly used in various applications, from car alarms to starter circuits. In this article, we’ll take a closer look at the JD1912 relay wiring diagram, how to install it, and answer some frequently asked questions.

What is a JD1912 Relay?

The JD1912 relay is a 12V DC 40A waterproof relay that is commonly used in automotive and industrial applications. This type of relay can handle high current and voltage loads, making it ideal for applications that require a lot of power.

Most JD1912 relays have four pins, which are normally open (NO), normally closed (NC), common (C), and the coil. The NO and NC pins allow the relay to switch between two circuits, while the coil is used to control the switching action of the relay.

JD1912 Relay Wiring Diagram

The JD1912 relay wiring diagram is relatively straightforward. Here’s what you need to know:

Pin Description Wire Color
C (Common) Connect to the power source that you want to switch Red
NO (Normally Open) Connect to the circuit that you want to turn on Green
NC (Normally Closed) Connect to the circuit that you want to turn off Black
Coil Connect to the switch that will control the relay White

When the switch is turned on, the coil of the JD1912 relay is energized, which causes the NO circuit to close and the NC circuit to open. When the switch is turned off, the opposite happens.

How to Install a JD1912 Relay

Installing a JD1912 relay is relatively simple. Here are the steps:

  1. Identify the power source, the circuit that you want to turn on, and the circuit that you want to turn off.
  2. Connect the C pin of the relay to the power source.
  3. Connect the NO pin of the relay to the circuit that you want to turn on.
  4. Connect the NC pin of the relay to the circuit that you want to turn off.
  5. Connect the coil of the relay to the switch that will control the relay.
  6. Test the circuit to ensure that it’s working properly.

FAQs

What is the maximum current and voltage rating for a JD1912 relay?

The maximum current rating for a JD1912 relay is 40A, while the maximum voltage rating is 12V DC.

What is the difference between a NO and NC circuit?

A NO circuit is normally open, which means that there is no current flow until the relay is activated. An NC circuit is normally closed, which means that there is current flow until the relay is activated.

What is the purpose of the coil in a JD1912 relay?

The coil in a JD1912 relay is used to control the switching action of the relay. When the coil is energized, the relay switches from the NC circuit to the NO circuit, and vice versa.

Can a JD1912 relay be used in a 24V DC circuit?

No, a JD1912 relay is only rated for 12V DC. Using it in a 24V DC circuit can cause the relay to fail or cause damage to other components in the circuit.

What are some common applications for a JD1912 relay?

JD1912 relays are commonly used in automotive applications, such as car alarms, starter circuits, and power windows. They are also used in industrial applications, such as automated machinery, HVAC systems, and lighting controls.

Conclusion

The JD1912 relay is a versatile and reliable component that is widely used in various applications. Understanding the JD1912 relay wiring diagram is essential for anyone working with this type of relay. By following the instructions in this article, you should be able to install and use a JD1912 relay with ease.